I get that this is just a meme, but for those who are curious about an actual mathematical argument, it is because Pythagoras’s theorem only works in Euclidean geometries (see proof below). In Euclidean geometry, distances must be real numbers of at least 0.

There exists at least one ∆ABC in a 2-D non-Euclidean plane G where (AB)² + (AC)² ≠ (BC)² and m∠A = π/2

Proof: Let G be a plane of constant positive curvature, i.e. analogous to the exterior surface of a sphere. Let A be any point in G and A’ the point of the furthest possible distance from A. A’ exists because the area of G is finite. Construct any line (i.e. form a circle on the surface of the “sphere”) connecting A and A’. Let this line be AA’. Then, construct another line connecting A and A’ perpendicular to the first line at point A. Let this line be (AA’)’ Mark the midpoints between A and A’ on this (AA’)’ as B and B’. Finally, construct a line connecting B and B’ that bisects both AA’ and (AA’)‘. Let this line be BB’. Mark the intersection points between BB’ and AA’ as C and C’. Now consider the triangle formed at ∆ABC. The measure of ∠A in this triangle is a right angle. The length of all legs of this triangle are, by construction, half the distance between A and A’, i.e. half the maximum distance between two points on G. Thus, AB = AC = BC. Let us define the measure of AB to be 1. Thus, 1² + 1² = 2 ≠ 1². Q.E.D.